Python3 石头 剪刀 布。分别用A B C表示。A＞B，B＞C，C＞A。本场中有且仅有一个最大，否则认为平局。键盘输入信息：每个玩家信息为一行，数量不超过100，信息两个字段，用空格隔开：玩家ID：一个仅有英文和数字构成，出拳用A，B，C表示，出拳时间为正整数。输出：赢家ID列表（一个或多个），每个ID一行，按字符串升序，如果没有赢家，输出'NuLl'字符串）

```python def get_winner(players): result = [] for player in players: if len(set(player[1] for player in players)) == 3: return 'NuLl' if 'A' in player[1 and 'B' in player[1]: result.append(player[0]) elif 'B' in player[1] and 'C' in player[1]: result.append(player[0]) 'C' in player[1] and 'A' in player[1]: result.append(player[0]) return sorted(result) players = [] = int(input("Enter the number of players: ")) for _ in range(n): player_info = input().split() players.append((player_info[0], player_info[1])) ners = get_winner(players) for winner in winners: print(winner) ``` 此代码中，首先定义了一个函数`get_winner(players)`来判断赢家。然后从键输入玩家信息，将其存储在列表`players`中。接着调用`get_winner(players)`函数得到赢家的ID列表，并按照字符串升序输出。如果没有赢家则输出'NuLl'字符串。